Type Alias anymap::AnyMap

source ·
pub type AnyMap = Map<dyn Any>;
Expand description

The most common type of Map: just using Any.

Why is this a separate type alias rather than a default value for Map<A>? Map::new() doesn’t seem to be happy to infer that it should go with the default value. It’s a bit sad, really. Ah well, I guess this approach will do.

Aliased Type§

struct AnyMap { /* private fields */ }